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cos(π+α)=-1/3,sin(3π/2-α)=sin(π/3+α)=1/3,cos(5π/6+α)=sin(α-π/4)=1/3,cos(π/4+α)=

分类: 作业答案 • 2021-12-18 17:06:04
问题描述：

cos(π+α)=-1/3,sin(3π/2-α)=
sin(π/3+α)=1/3,cos(5π/6+α)=
sin(α-π/4)=1/3,cos(π/4+α)=

答

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