(2sin2α/1+cos2α)*(cosα)^2/cos2α=多少
问题描述:
(2sin2α/1+cos2α)*(cosα)^2/cos2α=多少
答
(2sin2α/1+cos2α)*(cosα)^2/cos2α
=(2sin2α)/(2cos²α) *(cos²α)/(cos2α)
=sin2α/cos2α
=tan2α