π到π/3 sin（x+π/3）dx 定积分
问题描述：
π到π/3 sin（x+π/3）dx 定积分
答
∫(π→π/3) sin(x + π/3) dx
= ∫(π→π/3) sin(x + π/3) d(x + π/3)
= cos(x + π/3)：[π/3→π]
= cos(π + π/3) - cos(π/3 + π/3)
= 0
答
π到π/3 sin（x+π/3）dx 定积分
=-cos(x+π/3) | (π到π/3 )
=-cos(π/3+π/3)+cos(π+π/3)
=1/2-1/2
=0
答
∫sin(x+π/3) dx=∫sin(x+π/3) d(x+π/3)
=-cos(x+π/3)+C
所以原式=-cos(π/3+π/3)+cos(π+π/3)
=-cos(2π/3)-cos(π/3)
=1/2-1/2
=0