f(x)=ax+1/a(1-x),其中a>0,记f(x)在0=
问题描述:
f(x)=ax+1/a(1-x),其中a>0,记f(x)在0=
答
f(x)=ax+1/a(1-x)
=(a-1/a)x+1/a
若a-1/a>=0即a>=1,函数在x=0处取最小值为1/a
若a-1/a=