已知x/y=2/3,求x²-y²/xy÷[（x+y）（x-y/x）³]÷x/y²的值
问题描述：
已知x/y=2/3,求x²-y²/xy÷[（x+y）（x-y/x）³]÷x/y²的值
答
y=3x/2
=(x+y)(x-y)/xy*[x^3/(x+y)(x-y)^3]*(y^2/x)
=xy/(x-y)^2
=(3x^2/2)/(-x/2)^2
=(3/2)/(1/4)
=6谢谢了