三角形ABC中a^2+b^2=2c^2求（sin^2A+sin^2B）/Sin^2C
问题描述：
三角形ABC中a^2+b^2=2c^2求（sin^2A+sin^2B）/Sin^2C
答
正弦定理
（sin^2A+sin^2B）/Sin^2C = (a^2+b^2)/c^2 = 2c^2/c^2 = 2