sin(π+π/6)-cos(π+π/4)cos(-π/2)+1求值
问题描述:
sin(π+π/6)-cos(π+π/4)cos(-π/2)+1
求值
答
sin(π+π/6)-cos(π+π/4)cos(-π/2)+1
=-sin(π/6)+cos(π/4)cos(+π/2)+1
=-1/2+cos(π/4)*0+1
=1/2