sin(1-cosx)^2的导数
问题描述：
sin(1-cosx)^2的导数
这个符合函数的导数多少?最好带点过程
答
(1-cosx)'=sinx
[(1-cosx)^2]'
=(1-cosx)'*2(1-cosx)
=2sinx(1-cosx)
[sin(1-cosx)^2]'
=[(1-cosx)^2]'*cos(1-cosx)^2
=2sinx(1-cosx)cos(1-cosx)^2
若是求[sin(1-cosx)]^2的导数
则(1-cosx)'=sinx
[sin(1-cosx)]'
=(1-cosx)'*cos(1-cosx)
=sinxcos(1-cosx)
([sin(1-cosx)]^2)'
=[sin(1-cosx)]'*2sin(1-cosx)
=sinxcos(1-cosx)2sin(1-cosx)
=sinxsin(2-2cosx)