tan15度+cot15度
问题描述:
tan15度+cot15度
答
tan15°+cot15°
=sin15°/cos15°+cos15°/sin15°
=(sin²15°+cos²15°)/sin15°cos15°
=1/sin15°cos15°
=2/2sin15°cos15°
=2/sin30°
=2/(1/2)
=4
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答
tan15+cot15
=sin15/cos15+cos15/sin15
=(sin²15+cos²15)/(sin15cos15)
=1/[(1/2)sin(2×15)]
=2/sin30
=2/(1/2)
=4
答
tan15度+cot15度
=sin15°/cos15°+cos15°/sin15°
=(sin15°sin15°+cos15°cos15°)/(sin15°cos15°)
=2(sin15°sin15°+cos15°cos15°)/(2sin15°cos15°)
=2/(sin30°)
=2/(1/2)
=4