已知sinα=3/5且π/2扫码下载作业帮拍照答疑一拍即得

问题描述:

已知sinα=3/5且π/2

扫码下载作业帮
拍照答疑一拍即得

π/2sinα=3/5
所以π/2cosα=-4/5
tanα=-3/4
secα-tanα
=1/cosα-3/4
=1/(-4/5)-(-3/4)
=-5/4+3/4
=-1/2

sinα=3/5且π/2所以
π/2而
sin²α+cos²α=1

cosα=-4/5
tanα=sinα/cosα=-3/4
secα=1/cosα=-5/4
所以
secα-tanα=-5/4+3/4=-1/2