lim x →2 （2/2x-x^2 +1/x^2-3x+2）求极限
问题描述：
lim x →2 （2/2x-x^2 +1/x^2-3x+2）求极限
答
原式=lim[-2/x(x-2)+1/(x-1)(x-2)]
=lim[(-2x+2+x)/x(x-1)(x-2)]
=lim[-(x-2)/x(x-1)(x-2)]
==lim[(-1/x(x-1)]
=-1/2*1
=-1/2