观察,分析,猜想:1×2×3×4+1=52;2×3×4×5+1=112;3×4×5×6+1=192;4×5×6×7+1=292;n(n+1)(n+2)(n+3)+1=_.(n为整数)

问题描述:

观察,分析,猜想:1×2×3×4+1=52;2×3×4×5+1=112;3×4×5×6+1=192;4×5×6×7+1=292;n(n+1)(n+2)(n+3)+1=______.(n为整数)

∵1×2×3×4+1=[(1×4)+1]2=52
2×3×4×5+1=[(2×5)+1]2=112
3×4×5×6+1=[(3×6)+1]2=192
4×5×6×7+1=[(4×7)+1]2=292
∴n(n+1)(n+2)(n+3)+1=(n2+3×n+1)2
故答案为:n(n+1)(n+2)(n+3)+1=(n2+3×n+1)2