解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9（5）（x+2)^2=(2x+1)^2
问题描述：
解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9（5）（x+2)^2=(2x+1)^2
(6)9(x+3)^2=(2x-5)^2
快哦
答
(1 ) x^2 - 36=0 (x-6)(x+6) =0 x-6=0 x+6 =0 x1 =6 x2 =-6(2))(2x-1)^2 - 25 = 0 [( 2x-1)-5 ] [(2x-1)+5 ]=0 ( 2x-1)-5 =0 ( 2x-1)+5 =0 x1=3 x2=-2(3) x(2x+7)=0 x=0 2x+7=0 x1=0 x2= -7/2(4) x^2-6x+9=0 (x - 3)...