先化简再求值(a-2ab-b²/a)乘以a²+ab/a²-b²其中a=1,-3小于b小于负根号三且b为整数

问题描述:

先化简再求值(a-2ab-b²/a)乘以a²+ab/a²-b²其中a=1,-3小于b小于负根号三且b为整数

a=1,-3小于b小于负根号三且b为整数,b=-2(a-2ab-b²)/a乘以(a²+ab)/(a²-b²)=(a-2ab-b²/a乘以a(a+b)/[(a+b)(a-b)]=(a-2ab-b²)/(a-b)=(1-2b-b²)/(1-b)=(1+4-4)/(1+2)=1/3...