(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程

问题描述:

(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
关于换底公式的都懂不起哟

注明一下loga的n次方 b的m次方=(m/n)loga bloga b=lg b/lg a原式=(log2 3+log8 9)(log3 4+log9 8+log3 2)=[log2 3+(2/3)log2 3][2log3 2+(3/2)log3 2+log3 2]=(5/3)log2 3*(9/2)log3 2=(15/2)(lg 3/lg 2)(lg 2/lg 3)...