x/(4m-√2x)=(3m-√2x)/x (m为常数项)求x值全过程

问题描述:

x/(4m-√2x)=(3m-√2x)/x (m为常数项)求x值全过程

x^2=12m^2-7√2x+2x^2
整理得:x^2-7√2x+12m^2=0
x=(7√2±√[(-7√2)^2-4*12m^2]}/2
=[7√2±√(98-48√m^2)]/2