为得到函数y=cos(2x+π/3)的图象,只需将函数y=sin2x的图象怎样移动谢谢了,大神帮忙啊
问题描述：
为得到函数y=cos(2x+π/3)的图象,只需将函数y=sin2x的图象怎样移动谢谢了,大神帮忙啊
答
y=cos(2x+π/3)=sin(2x+n/3+ π/2) =sin(π/2+2x+π/3) =sin(2x+5π/6) =sin[2(x+5π/12)]