复数( -1+根号3i)的5次方/1+根号3i的值是

问题描述:

复数( -1+根号3i)的5次方/1+根号3i的值是

原式=[2(cos2π/3+isin2π/3)]^5/[2(cosπ/3+isinπ/3)
=32(cos10π/3+usin10/3)/[2(cosπ/3+isinπ/3)]
=16(cos3π+isin3π)
=-16