已知1/a+1/b=1,则(3a-2ab-3b)/(a+3ab-b)的值是多少

问题描述:

已知1/a+1/b=1,则(3a-2ab-3b)/(a+3ab-b)的值是多少

∵1/a-1/b=1
∴(b-a)/ab=1
a-b=-ab
∴(3a-2ab-3b)/(a+3ab-b)
=[3(a-b)-2ab]/[(a-b)+3ab]
=(-3ab-2ab)/(-ab+3ab)
=(-5ab)/(2ab)
=-2.5