若x/3=y/4=z/5(xyz≠0),则x+y+z/2x=多少

问题描述:

若x/3=y/4=z/5(xyz≠0),则x+y+z/2x=多少

设x/3=y/4=z/5=k
则x=3k,y=4k,z=5k
(x+y+z)/2x
=(3k+4k+5k)/6k
=12k/6k
=2