loga(2x+3)>loga(5x-6),求x的取值范围.
问题描述:
loga(2x+3)>loga(5x-6),求x的取值范围.
答
loga(2x+3)>loga(5x-6)
先求定义域
{2x+3>0
{5x-6>0
==>
{x>-3/2
{x
-3/25x-6
3x