先化简,再求值:m+1/2m2−2m•(2m/m+1)2−(1/m−1−1/m+1),其中m=2.

问题描述:

先化简,再求值:

m+1
2m2−2m
•(
2m
m+1
)2−(
1
m−1
1
m+1
),其中m=2.

原式=

m+1
2m(m−1)
4m2
(m+1)2
-
m+1−m+1
(m+1)(m−1)

=
2m
(m−1)(m+1)
-
2
(m+1)(m−1)

=
2m−2
(m+1)(m−1)

=
2
m+1

当m=2时,原式=
2
2+1
=
2
3