函数y=x²(2-x) (x≥0)最大值最小值怎么求?
问题描述:
函数y=x²(2-x) (x≥0)最大值最小值怎么求?
答
y=x²(2-x) y' = 4x-3x^2=0x(3x-4)=0x=0 or 4/3f''(x) = 4-6xf''(0)= 4> 0 (min)f''(4/3)无穷)y = -无穷
函数y=x²(2-x) (x≥0)最大值最小值怎么求?
y=x²(2-x) y' = 4x-3x^2=0x(3x-4)=0x=0 or 4/3f''(x) = 4-6xf''(0)= 4> 0 (min)f''(4/3)无穷)y = -无穷