化简求值:a^2-ab/a^2-b^2.a=根号2b

问题描述:

化简求值:a^2-ab/a^2-b^2.a=根号2b

(a^2-ab)/(a^2-b^2)
=[a(a-b)]/[(a+b)(a-b)]
=a/(a+b)
=(√2b)/(√2b+b)
=(√2)/(√2+1)
=2-√2为什么(√2)/(√2+1) =2-√2分母有理化分子分母同时乘以(√2-1)(√2)/(√2+1)=[(√2)×(√2-1)]/[(√2+1)×(√2-1)]=(2-√2)/[(√2)^2-1^2]=2-√2不懂可以继续追问