先去括号,再合并同类项: (1)(x+y-z)+(x-y+z)-(x-y-z); (2)3(2x2-y2)-2(3y2-2x2).
问题描述:
先去括号,再合并同类项:
(1)(x+y-z)+(x-y+z)-(x-y-z);
(2)3(2x2-y2)-2(3y2-2x2).
答
(1)原式=x+y-z+x-y+z-x+y+z
=x+y+z;
(2)原式=6x2-3y2-6y2+4x2
=10x2-9y2.