先去括号,再合并同类项:1-2(x-y-1)1-2(x-y-1)原式=1-2x+2y+2=1+2-2x+2y=3-2x+2y
问题描述:
先去括号,再合并同类项:1-2(x-y-1)
1-2(x-y-1)
原式=1-2x+2y+2
=1+2-2x+2y
=3-2x+2y
答
是最终的答案
先去括号,再合并同类项:1-2(x-y-1)
1-2(x-y-1)
原式=1-2x+2y+2
=1+2-2x+2y
=3-2x+2y
是最终的答案