若定义P☆Q=5P+3Q,P¤Q=3P-5Q,那么(3¤2/3)☆0.6=_.

问题描述:

若定义P☆Q=5P+3Q,P¤Q=3P-5Q,那么(3¤

2
3
)☆0.6=______.

(3¤

2
3
)☆0.6,
=(3×3-5×
2
3
)☆0.6,
=(9-
10
3
)☆0.6,
=
17
3
☆0.6,
=5×
17
3
+3×0.6,
=
85
3
+
9
5

=
452
15

故答案为:
452
15