设f(x)=x(x-1)(x-2)……(x-100)则f(0)的导数为多少

问题描述:

设f(x)=x(x-1)(x-2)……(x-100)则f(0)的导数为多少

f=x*[(x-1)...(x-100)]求导f'=[(x-1)...(x-100)]+x*@ 后式不用求,将0代入,f'(0)=1*2*3..+0*@=100!答案就是100的阶乘