方程,12/x+12/y=1 x-y=10

问题描述:

方程,12/x+12/y=1 x-y=10

12y/xy+12x/xy=112y+12x=xy将 x-y=10 y=x-10 代入12(x-10)+12x=x*(x-10)12x-120+12x=x^2-10xx^2-10x-24x+120=0x^2-34x+120=0(x-30)(x-4)=0x=30 or x=4if x=30 y=30-10=20if x=4 y=4-10=-6