已知a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5≤f(x)≤1 (1)求常数a,b的值 (2)设g(x)=f(x+π/2)且lgg(x)>0,求g(x)的单调 我算了好几遍第一问,a+b

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已知a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5≤f(x)≤1 (1)求常数a,b的值 (2)设g(x)=f(x+π/2)且lgg(x)>0,求g(x)的单调 我算了好几遍第一问,a+b