已知tanA=3,tanB=-4/3,tan(A+B)的值

问题描述:

已知tanA=3,tanB=-4/3,tan(A+B)的值

tan(A+B)=(tanA+tanB)/(1-tanAtanB)
=(3-4/3)/(1-3*(-4/3)
=(5/3)/(5)
=1/3