已知tanA=3,tanB=-4/3,tan(A+B)的值
问题描述:
已知tanA=3,tanB=-4/3,tan(A+B)的值
答
tan(A+B)=(tanA+tanB)/(1-tanAtanB)
=(3-4/3)/(1-3*(-4/3)
=(5/3)/(5)
=1/3