已知x^2_5x_2009=0,则代数式(x_2)^2_(x_1)^2+1/x_2的值为( )若分式3/x_1的值是正整数,则整数x的值是
问题描述:
已知x^2_5x_2009=0,则代数式(x_2)^2_(x_1)^2+1/x_2的值为( )若分式3/x_1的值是正整数,则整数x的值是
答
1.已知x^2-5x-2009=0,则x^=5x+2009,代数式(x-2)^2-(x-1)^2+1/(x-2)=-(2x-3)+1/(x-2)=(-2x^+7x-5)/(x-2)=(-10x-4018+7x-5)/(x-2)=(-3x-4023)/(x-2)=-3-4029/(x-2),它的值为(繁 ).请检查题目.2.若分式3/(x-1)的值...