分解因式x2-y2-3x-3y=_.
问题描述:
分解因式x2-y2-3x-3y=______.
答
x2-y2-3x-3y
=(x2-y2)-(3x+3y)
=(x-y)(x+y)-3(x+y)
=(x+y)(x-y-3).
故答案为:(x+y)(x-y-3).