分解因式x2-y2-3x-3y=_.

问题描述:

分解因式x2-y2-3x-3y=______.

x2-y2-3x-3y
=(x2-y2)-(3x+3y)
=(x-y)(x+y)-3(x+y)
=(x+y)(x-y-3).
故答案为:(x+y)(x-y-3).