初一化简求值[(-1/2×x^3×y^4)^3+(-1/6×x×y^2)^2×3x×y^2]÷（-1/2×x×y^2)^3其中,x=-2 y=1/2
问题描述：
初一化简求值
[(-1/2×x^3×y^4)^3+(-1/6×x×y^2)^2×3x×y^2]÷（-1/2×x×y^2)^3
其中,x=-2 y=1/2
答
原式=[(-1/2×-1^3×1/2^4)^3+(-1/6×-1×1/2^2)^2×3×-2×1/2^2]÷（-1/2×-2×1/2^2)^3
=[(-1/2×-1×1/16)^3+(-1/6×-1×1/4)^2×3×-2×1/4]÷（-1/2×-2×1/4)^3
=[(1/32)^3+(1/24)^2×3×-2×1/4]÷（1/4)^3
=[(1/32768+1/576×3×-2×1/4]÷64
=[(1/32768-1/384]÷64
=1/32768÷64-1/384÷64
=1/512-1/6
=3/1536-256/1536
=-253/1536
答
冷风你数学退步了啊!严肃批评!
原式=[(-1/2×-1^3×1/2^4)^3+(-1/6×-1×1/2^2)^2×3×-2×1/2^2]÷（-1/2×-2×1/2^2)^3
=[(-1/2×-1×1/16)^3+(-1/6×-1×1/4)^2×3×-2×1/4]÷（-1/2×-2×1/4)^3
=[(1/32)^3+(1/24)^2×3×-2×1/4]÷（1/4)^3
=[(1/32768+1/576×3×-2×1/4]÷64
=[(1/32768-1/384]÷64
=1/32768÷64-1/384÷64
=1/512-1/6
=3/1536-256/1536
=-253/1536
另外：LS你抄的太猛了吧,一模一样