对于满足03或x
问题描述:
对于满足03或x
答
px-p>4x-3-x^2
p(x-1)>4x-3-x^2
p(x-1)>-(x^2-4x+3)
p(x-1)>-(x-3)(x-1)
1.x=1,0>0,空集
2.x>1,p>-(x-3)
-(x-3)3
3.x4
x