化简求值:2x²y-[x²y+2(xy²-xy)+y]+y,其中x²=2x+1,y=2011/20122x²y-[x²y+2(x²y-xy)+y]+y,其中x²=2x+1,y=2011/2012

问题描述:

化简求值:2x²y-[x²y+2(xy²-xy)+y]+y,其中x²=2x+1,y=2011/2012
2x²y-[x²y+2(x²y-xy)+y]+y,其中x²=2x+1,y=2011/2012

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2x²y-[x²y+2(x²y-xy)+y]+y
=2x²y-x²y-2x²y+2xy-y+y
=-x²y+2xy
=-(x²-2x)y
=-y
=-2011/2012