若x2+x-2=0,则x3+2x2-x+2007=_.

问题描述:

若x2+x-2=0,则x3+2x2-x+2007=______.

∵x2+x-2=0,
∴x2+x=2,
∴x3+2x2-x+2007=x3+x2+x2-x+2007=x(x2+x)+x2-x+2007=2x+x2-x+2007=x2+x+2007=2009.
故答案为2009.