解方程组(x+y)/4-(2x-y)/3=-1 ① 6(x+y)-4(2x-y)=16 ②

问题描述:

解方程组(x+y)/4-(2x-y)/3=-1 ① 6(x+y)-4(2x-y)=16 ②

(x+y)/4-(2x-y)/3=-1 ①通分得3(x+y)-4(2x-y)=-12整理得(3)-5x+7y=-12
6(x+y)-4(2x-y)=16 ②整理后得(4)-x+5y=8--两边同时×5,得(5)-5x+25y=40
(3)和(5)相减
18y=52
y=26/9 代入到(4)
x=5y-8=5*26/9-8=58/9

(x+y)/4-(2x-y)/3=-1 ------------------------(1)
6(x+y)-4(2x-y)=16 ------------------------(2)
转换设x+y=A, 2x-y=B, 则转换后的是:
A/4-B/3=-1 ----------------------------(3)
6A-4B=16 ----------------------------(4)
(3)*12 得: 3A-4B=-12 --------------(5)
(4)-(5) 得: 3A=28; A=28/3
(4)-2*(5) 得: 4B=40, B=10
则: x+y=28/3 ------------------------------(6)
2x-y=10 ------------------------------(7)
(6)+(7) 得: 3x=58/3, x=58/9
y=2x-10=26/9
x=58/9, y= 26/9