化简:(1)x²-2x-3/x²+2x²-15x (2)x的四次方-1/x的四次方+2x²+1(3)x的三次方+x²+x+1/1-x² (4)a²-c²+b²+2ab/a²-c²-b²-2ab
问题描述:
化简:(1)x²-2x-3/x²+2x²-15x (2)x的四次方-1/x的四次方+2x²+1
(3)x的三次方+x²+x+1/1-x² (4)a²-c²+b²+2ab/a²-c²-b²-2ab
答
(1)、x²+2x²-15x 写错了吧?是不是x^3+2x²-15x 呢
显然x²-2x-3=(x-3)(x+1),而x^3+2x²-15x =x(x²+2x-15)=x(x+5)(x-3)
所以
(x²-2x-3) / (x^3+2x²-15x) =(x-3)(x+1) / x(x+5)(x-3) = (x+1) / x(x+5)
(2)、
x的四次方-1 / x的四次方+2x²+1
=(x^4 -1) /(x^4+2x²+1)
=(x²+1)(x²-1) / (x²+1)²
=(x²-1) / (x²+1)
(3)、
x^3+x²+x+1 /1-x²
=(x+1)(x²+1) / (1-x)(1+x)
= (x²+1)/(1-x)
(4)、
(a²-c²+b²+2ab) / (a²-c²-b²-2ab)
=[(a+b)²-c²] / [a²-(b+c)²]
=(a+b+c)(a+b-c) / (a-b-c)(a+b+c)
=(a+b-c) / (a-b-c)
答
1、原式=[(x-3)(x+1)]/[(x-3)(x+5)]=(x+1)/(x+5)
2、原式=[(x²+1)(x²-1)]/(x²+1)²=(x²-1)/(x²+1)
3、原式=[(x²+1)(x+1)]/(1-x)(1+x)=(x²+1)/(1-x)
4、原式无法化简