已知弧长604.25,弦长595.66,求半径?急,谁能帮我算算

问题描述:

已知弧长604.25,弦长595.66,求半径?急,谁能帮我算算

已知弧长C=604.25,弦长L=595.66,求半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=1000
R1=1029.86
R2=1032.25
R3=1032.27
R4=1032.27
R=1032.27