圆C1:x∧2+y∧2+2x+4y-3=0与圆C2:x∧2+y∧2-4x+2y+4=0的公切线有

问题描述:

圆C1:x∧2+y∧2+2x+4y-3=0与圆C2:x∧2+y∧2-4x+2y+4=0的公切线有

圆C1:(x+1)∧2+(y+2)∧2=8与圆C2:(x-2)∧2+(y+1)∧2=1
C1C2=√10
求:(x+1)∧2+(y+2)∧2=9-4√2 与 (x-2)∧2+(y+1)∧2=1+4√2 交点A,B
AC2,BC2//公切线