将函数2sin(2x+π/3)+1的图像向左平移π/6个单位,再向商平移3个单位,所得解析式是
问题描述：
将函数2sin(2x+π/3)+1的图像向左平移π/6个单位,再向商平移3个单位,所得解析式是
答
将函数y=2sin(2x+π/3)+1的图像向左平移π/6个单位，得
y=2sin(2x+2π/3)+1
再向商平移3个单位,所得解析式是
y＝2sin(2x+2π/3)+4。
答
y=2sin(2x+π/3)+1
=2sin[2(x+π/6)]+1
向左平移π/6个单位:
y=2sin[2(x+π/6+π/6)]+1
=2sin(2x+2π/3)+1
再向上平移3个单位:
y=2sin(2x+2π/3)+1+3
=2sin(2x+2π/3)+4