计算:(1/x+1/x+3)×2+x-2/x+3=1,我算不出来,有X平方的,
问题描述:
计算:(1/x+1/x+3)×2+x-2/x+3=1,我算不出来,有X平方的,
答
(1/x+1/(x+3))×2+(x-2)/(x+3)=12/x+2/(x+3)+(x-2)/(x+3)=12/x+2/(x+3)+(x-2)/(x+3)=12/x+x/(x+3)=1两边同乘以x(x+3)有2(x+3)+x^2=x(x+3)2x+6+x^2=x^2+3x2x+6=3xx=6经检验x=6是原方程的根注:去分母后两...