解方程x²+y²-6x+8y+25=0
问题描述:
解方程x²+y²-6x+8y+25=0
答
x²+y²-6x+8y+25=0
x²-6x+9+y²+8y+16=0
(X-3)²+(Y+4)²=0
X-3=0,Y+4=0
X=3,Y=-4
答
(X-3)²+(Y+4)²=0 x=3 y=-4
答
解由x^2+y^2-6x+8y+25=0
得x^2-6x+y^2+8y+25=0
即x^2-6x+9+y^2+8y+16=0
即(x-3)^2+(y+4)^2=0
即x=3,y=-4