计算①x²-4/x²-4x+3÷x²+3x+2/x²-x②2x+6/4-4x+x²÷(x+3)·x²+x-6/3-x
问题描述:
计算①x²-4/x²-4x+3÷x²+3x+2/x²-x②2x+6/4-4x+x²÷(x+3)·x²+x-6/3-x
答
①x²-4/x²-4x+3÷x²+3x+2/x²-x=(x²-4)/(x²-4x+3)÷(x²+3x+2)/(x²-x)=(x-2)(x+2)/(x-1)(x-3)÷(x+1)(x+2)/x(x-1)=x(x-2)(x+2)(x-1)/[(x-1)(x-3)(x+1)(x+2)]=(x²-2x)/...