[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
问题描述:
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
答
sina×(-cosa)/-cosa×(-sina)=-1
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
sina×(-cosa)/-cosa×(-sina)=-1