设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
问题描述:
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
答
lim[(x^2+1)/(x+1) -ax-b]
=lim[(x+1)-2x/(x+1)-ax-b]
=lim[(1-a)x-(1+b)]
=0
1-a=0 a=1
1+b=0 b=-1