用适当的方法解方程: (1)(2x-3)2=9(2x+3)2; (2)2x2-8x+6=0; (3)(5x-1)2=3(5x-1); (4)(x+1)2=-(x+1)+56.
问题描述:
用适当的方法解方程:
(1)(2x-3)2=9(2x+3)2;
(2)2x2-8x+6=0;
(3)(5x-1)2=3(5x-1);
(4)(x+1)2=-(x+1)+56.
答
(1)开方得:2x-3=3(2x+3)或2x-3=-3(2x+3),解得:x1=-3,x2=-34;(2)分解因式得:(2x-6)(x-1)=0,可得2x-6=0或x-1=0,解得:x1=3,x2=1;(3)方程变形得:(5x-1)2-3(5x-1)=0,分解因式得:(5x-1)...