△ABC的三个内角成等差数列,(A>B>C),若tanA,tanC是方程x(x-3)+2=根号3*(x-1)的两个根,且△ABC的面积为3-根号3,求a的长度.
问题描述:
△ABC的三个内角成等差数列,(A>B>C),若tanA,tanC是方程x(x-3)+2=根号3*(x-1)的两个根,
且△ABC的面积为3-根号3,求a的长度.
答
△ABC的三个内角成等差数列,(A>B>C),若tanA,tanC是方程x(x-3)+2=根号3*(x-1)的两个根,
且△ABC的面积为3-根号3,求a的长度.