sin(-11/6π)+cos12/5π×tan4π化简
问题描述：
sin(-11/6π)+cos12/5π×tan4π化简
答
sin(-11/6π)=sin(2π-11/6π)=1/2
cos12/5π×tan4π=0
所以原式答案为1/2
答
sin(-11/6π)+cos12/5π×tan4π
=sin(-11/6π+2π)+cos12/5π×tan(4π-4π)
=sin(1/6π)+cos12/5π×tan0
=1/2+cos12/5π×0
=1/2